If you drop a basketball from a certain height without putting any force into it, how do you measure its speed?|||V = gt
or
V = sqrt(2gx)
where V is the speed; g = 9.8 m/s/s (the acceleration of the ball due to the force of gravity); t is the elapsed time and x is the distance fallen|||Everything falls at the same rate. The contributing factor is our atmosphere. Physics experiments put a feather and a rock in a vacuum chamber and release them at equal heights. They drop at the same speed.|||The basketball's speed changes all the time since it's accelerated by the force of gravity.
You can find the velocity at any given time using the formula: v=g*t, where g is the acceleration applied by gravity (something like 9.8) and t is the time in seconds from the release of the ball.
If you drop the ball from a certain height and would like to know its speed a moment before it hits the ground, measure the height (h) and use the following formula:
v^2 = 2*g*h.
For example: Let's say we drop the ball from a height of 10 meters.
v^2 = 2*9.8*10 = 196
So v = sqrt(196) = 14 m/s.|||haha i dont no what theyre even talking about
speed = distance / time
measure the distance = 10 m
time the fall = 2 secs
10 / 5 = 2
so the sped of the ball is going at 2 m/s
the others try and complicate it haha
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